2x^2+2y^2+8y=0

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Solution for 2x^2+2y^2+8y=0 equation:


Simplifying
2x2 + 2y2 + 8y = 0

Reorder the terms:
2x2 + 8y + 2y2 = 0

Solving
2x2 + 8y + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8y' to each side of the equation.
2x2 + 8y + -8y + 2y2 = 0 + -8y

Combine like terms: 8y + -8y = 0
2x2 + 0 + 2y2 = 0 + -8y
2x2 + 2y2 = 0 + -8y
Remove the zero:
2x2 + 2y2 = -8y

Add '-2y2' to each side of the equation.
2x2 + 2y2 + -2y2 = -8y + -2y2

Combine like terms: 2y2 + -2y2 = 0
2x2 + 0 = -8y + -2y2
2x2 = -8y + -2y2

Divide each side by '2'.
x2 = -4y + -1y2

Simplifying
x2 = -4y + -1y2

Reorder the terms:
x2 + 4y + y2 = -4y + 4y + -1y2 + y2

Combine like terms: -4y + 4y = 0
x2 + 4y + y2 = 0 + -1y2 + y2
x2 + 4y + y2 = -1y2 + y2

Combine like terms: -1y2 + y2 = 0
x2 + 4y + y2 = 0

The solution to this equation could not be determined.

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